Easy

Binary SearchC++

Full explanation · Time O(logn) · Space O(1)

// Time:  O(logn)
// Space: O(1)

class Solution {
public:
    int search(vector<int>& nums, int target) {
        int left = 0, right = nums.size() - 1;
        while (left <= right) {
            auto mid = left + (right-left) / 2;
            if (nums[mid] > target) {
                right = mid - 1;
            } else if (nums[mid] < target) {
                left = mid + 1;
            } else {
                return mid;
            }
        }
        return -1;
    }
};