Check if Array Is Sorted and Rotated — Python

# Time:  O(n)
# Space: O(1)

class Solution(object):
    def check(self, nums):
        """
        :type nums: List[int]
        :rtype: bool
        """
        count = 0
        for i in xrange(len(nums)):
            if nums[i] > nums[(i+1)%len(nums)]:
                count += 1
                if count > 1:
                    return False
        return True