Easy
Count Common Words With One Occurrence — Python
Full explanation · Time O(m + n) · Space O(m + n)
# Time: O(m + n)
# Space: O(m + n)
import collections
class Solution(object):
def countWords(self, words1, words2):
"""
:type words1: List[str]
:type words2: List[str]
:rtype: int
"""
cnt = collections.Counter(words1)
for c in words2:
if cnt[c] < 2:
cnt[c] -= 1
return sum(v == 0 for v in cnt.itervalues())