Hard
Count Subarrays With Fixed Bounds — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// two pointers
class Solution {
public:
long long countSubarrays(vector<int>& nums, int minK, int maxK) {
int64_t result = 0;
int left = 0;
vector<int> right(2, -1);
for (int i = 0; i < size(nums); ++i) {
if (nums[i] < minK || nums[i] > maxK) {
left = i + 1;
continue;
}
if (nums[i] == minK) {
right[0] = i;
}
if (nums[i] == maxK) {
right[1] = i;
}
result += max(min(right[0], right[1]) - left + 1, 0);
}
return result;
}
};