Medium
Equal Tree Partition — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(n)
# Space: O(n)
import collections
class Solution(object):
def checkEqualTree(self, root):
"""
:type root: TreeNode
:rtype: bool
"""
def getSumHelper(node, lookup):
if not node:
return 0
total = node.val + \
getSumHelper(node.left, lookup) + \
getSumHelper(node.right, lookup)
lookup[total] += 1
return total
lookup = collections.defaultdict(int)
total = getSumHelper(root, lookup)
if total == 0:
return lookup[total] > 1
return total%2 == 0 and (total/2) in lookup