Medium
Friend Circles — Python
Full explanation · Time O(n^2) · Space O(n)
# Time: O(n^2)
# Space: O(n)
class Solution(object):
def findCircleNum(self, M):
"""
:type M: List[List[int]]
:rtype: int
"""
class UnionFind(object):
def __init__(self, n):
self.set = range(n)
self.count = n
def find_set(self, x):
if self.set[x] != x:
self.set[x] = self.find_set(self.set[x]) # path compression.
return self.set[x]
def union_set(self, x, y):
x_root, y_root = map(self.find_set, (x, y))
if x_root != y_root:
self.set[min(x_root, y_root)] = max(x_root, y_root)
self.count -= 1
circles = UnionFind(len(M))
for i in xrange(len(M)):
for j in xrange(len(M)):
if M[i][j] and i != j:
circles.union_set(i, j)
return circles.count