Hard
Maximum Equal Frequency — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
class Solution {
public:
int maxEqualFreq(vector<int>& nums) {
int result = 0;
unordered_map<int, int> count;
vector<int> freq(nums.size() + 1);
for (int i = 0; i < nums.size(); ++i) {
--freq[count[nums[i]]];
++freq[count[nums[i]] + 1];
const auto c = ++count[nums[i]];
if (freq[c] * c == (i + 1) && (i + 1) < nums.size()) {
result = (i + 1) + 1;
}
const auto& remain = (i + 1) - freq[c] * c;
if (freq[remain] == 1 && (remain == 1 || remain == c + 1)) {
result = (i + 1);
}
}
return result;
}
};