Hard
Minimum Window Substring — C++
Full explanation · Time O(n) · Space O(k)
// Time: O(n)
// Space: O(k)
class Solution {
public:
string minWindow(string s, string t) {
unordered_map<int, int> count;
for (const auto& c : t) {
++count[c];
}
int remain = t.length();
int left = -1, right = -1;
for (int i = 0, j = 0; j < s.length(); ++j) {
remain -= count[s[j]]-- > 0;
if (remain) {
continue;
}
while (count[s[i]] < 0) {
++count[s[i++]];
}
if (right == -1 || j - i + 1 < right - left + 1) {
left = i;
right = j;
}
}
return left >= 0 ? s.substr(left, right - left + 1) : "";
}
};
// Time: O(n)
// Space: O(k)
class Solution2 {
public:
string minWindow(string s, string t) {
if (s.empty() || s.length() < t.length()) {
return "";
}
const int ASCII_MAX = 256;
vector<int> exp_cnt(ASCII_MAX, 0);
vector<int> cur_cnt(ASCII_MAX, 0);
int cnt = 0;
int start = 0;
int min_start = 0;
int min_width = numeric_limits<int>::max();
for (const auto& c : t) {
++exp_cnt[c];
}
for (int i = 0; i < s.length(); ++i) {
if (exp_cnt[s[i]] > 0) {
++cur_cnt[s[i]];
if (cur_cnt[s[i]] <= exp_cnt[s[i]]) { // Counting expected elements.
++cnt;
}
}
if (cnt == t.size()) { // If window meets the requirement.
while (exp_cnt[s[start]] == 0 || // Adjust left bound of window.
cur_cnt[s[start]] > exp_cnt[s[start]]) {
--cur_cnt[s[start]];
++start;
}
if (min_width > i - start + 1) { // Update minimum window.
min_width = i - start + 1;
min_start = start;
}
}
}
if (min_width == numeric_limits<int>::max()) {
return "";
}
return s.substr(min_start, min_width);
}
};