Hard
Orderly Queue — C++
Full explanation · Time O(n^2) · Space O(n)
// Time: O(n^2)
// Space: O(n)
class Solution {
public:
string orderlyQueue(string S, int K) {
if (K == 1) {
auto result{S};
for (int i = 1; i < S.length(); ++i) {
result = min(result, S.substr(i) + S.substr(0, i));
}
return result;
}
sort(S.begin(), S.end());
return S;
}
};