Easy
Points That Intersect With Cars — Python
Full explanation · Time O(nlogn) · Space O(1)
# Time: O(nlogn)
# Space: O(1)
# sort, line sweep
class Solution(object):
def numberOfPoints(self, nums):
"""
:type nums: List[List[int]]
:rtype: int
"""
nums.sort()
result = 0
curr = nums[0]
for i in xrange(1, len(nums)):
if nums[i][0] <= curr[1]:
curr[1] = max(curr[1], nums[i][1])
else:
result += curr[1]-curr[0]+1
curr = nums[i]
result += curr[1]-curr[0]+1
return result