Medium
Replace Words — Python
Full explanation · Time O(n) · Space O(t)
# Time: O(n)
# Space: O(t), t is the number of nodes in trie
import collections
class Solution(object):
def replaceWords(self, dictionary, sentence):
"""
:type dictionary: List[str]
:type sentence: str
:rtype: str
"""
_trie = lambda: collections.defaultdict(_trie)
trie = _trie()
for word in dictionary:
reduce(dict.__getitem__, word, trie).setdefault("_end")
def replace(word):
curr = trie
for i, c in enumerate(word):
if c not in curr:
break
curr = curr[c]
if "_end" in curr:
return word[:i+1]
return word
return " ".join(map(replace, sentence.split()))