Easy
Shortest Unsorted Continuous Subarray — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int findUnsortedSubarray(vector<int>& nums) {
const auto n = nums.size();
auto left = -1, right = -2;
auto max_from_left = nums[0], min_from_right = nums.back();
for (int i = 1; i < n; ++i) {
max_from_left = max(max_from_left, nums[i]);
min_from_right = min(min_from_right, nums[n - 1 - i]);
if (nums[i] < max_from_left) {
right = i;
}
if (nums[n - 1 - i] > min_from_right) {
left = n - 1 - i;
}
}
return right - left + 1;
}
};