Easy
Sort Array By Parity II — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
class Solution(object):
def sortArrayByParityII(self, A):
"""
:type A: List[int]
:rtype: List[int]
"""
j = 1
for i in xrange(0, len(A), 2):
if A[i] % 2:
while A[j] % 2:
j += 2
A[i], A[j] = A[j], A[i]
return A