Medium
Split Array Into Maximum Number of Subarrays — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// greedy
class Solution {
public:
int maxSubarrays(vector<int>& nums) {
int result = 0, curr = 0;
for (const auto& x : nums) {
curr = curr ? curr & x : x;
if (!curr) {
++result;
}
}
return max(result, 1);
}
};