Medium
Split Array Into Maximum Number of Subarrays — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# greedy
class Solution(object):
def maxSubarrays(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = curr = 0
for x in nums:
curr = curr&x if curr else x
if not curr:
result += 1
return max(result, 1)