Hard
Split Array Largest Sum — Python
Full explanation · Time O(nlogs) · Space O(1)
# Time: O(nlogs), s is the sum of nums
# Space: O(1)
class Solution(object):
def splitArray(self, nums, m):
"""
:type nums: List[int]
:type m: int
:rtype: int
"""
def check(nums, m, s):
cnt, curr_sum = 1, 0
for num in nums:
curr_sum += num
if curr_sum > s:
curr_sum = num
cnt += 1
return cnt <= m
left, right = max(nums), sum(nums)
while left <= right:
mid = left + (right - left) // 2
if check(nums, m, mid):
right = mid - 1
else:
left = mid + 1
return left