Easy
Two Sum — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
class Solution {
public:
vector<int> twoSum(vector<int>& nums, int target) {
unordered_map<int, int> lookup;
for (int i = 0; i < nums.size(); ++i) {
if (lookup.count(target - nums[i])) {
return {lookup[target - nums[i]], i};
}
lookup[nums[i]] = i;
}
return {};
}
};